<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Susskind&#8217;s lectures on cosmology</title>
	<atom:link href="http://www.nonequilibrium.net/susskinds-lectures-cosmology/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.nonequilibrium.net/susskinds-lectures-cosmology/</link>
	<description>Cosmology, turbulence, markets, non-equilibrium QFT and much more. No nonsense, just science</description>
	<lastBuildDate>Wed, 13 Jan 2010 17:43:51 +0000</lastBuildDate>
	<generator>http://wordpress.org/?v=2.9.1</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<xhtml:meta xmlns:xhtml="http://www.w3.org/1999/xhtml" name="robots" content="noindex" />
	<item>
		<title>By: BlackGriffen</title>
		<link>http://www.nonequilibrium.net/susskinds-lectures-cosmology/comment-page-1/#comment-9220</link>
		<dc:creator>BlackGriffen</dc:creator>
		<pubDate>Wed, 05 Aug 2009 08:55:09 +0000</pubDate>
		<guid isPermaLink="false">http://www.nonequilibrium.net/?p=4162#comment-9220</guid>
		<description>Ah, he got to the constant later in the lecture.</description>
		<content:encoded><![CDATA[<p>Ah, he got to the constant later in the lecture.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: BlackGriffen</title>
		<link>http://www.nonequilibrium.net/susskinds-lectures-cosmology/comment-page-1/#comment-9219</link>
		<dc:creator>BlackGriffen</dc:creator>
		<pubDate>Wed, 05 Aug 2009 08:47:48 +0000</pubDate>
		<guid isPermaLink="false">http://www.nonequilibrium.net/?p=4162#comment-9219</guid>
		<description>There was an omission in his solution to that differential equation and a mistake in the second lecture. He uses the guess and check method, but the equation is separable, so he misses his free parameter. The full answer is:

[tex]a = \left( a_0^{3/2} + K * (t - t_0) \right)^{2/3}[/tex]

The form of K depends on the choice of the form of M, and the free parameter is, of course, [tex]c = a_0^{3/2} - K * t_0[/tex]. Basically, he assumed that a = 0 corresponds to t = 0. 

The mistake is kind of funny because error in the video is that he said, offhandedly, at some point that an object at escape velocity goes logarithmically. Well, this is the solution to the equation for how an object at escape velocity behaves, he just didn&#039;t notice.</description>
		<content:encoded><![CDATA[<p>There was an omission in his solution to that differential equation and a mistake in the second lecture. He uses the guess and check method, but the equation is separable, so he misses his free parameter. The full answer is:</p>
<p><img src='http://www.nonequilibrium.net/latexrender/pictures/d26163d50e228aa55bb3c6e2d0f921d0.gif' title='a = \left( a_0^{3/2} + K * (t &amp;#8211; t_0) \right)^{2/3}' alt='a = \left( a_0^{3/2} + K * (t &amp;#8211; t_0) \right)^{2/3}' align=absmiddle/></p>
<p>The form of K depends on the choice of the form of M, and the free parameter is, of course, <img src='http://www.nonequilibrium.net/latexrender/pictures/1be8b1efc45eaedb67c39e5432c5ed0c.gif' title='c = a_0^{3/2} &amp;#8211; K * t_0' alt='c = a_0^{3/2} &amp;#8211; K * t_0' align=absmiddle/>. Basically, he assumed that a = 0 corresponds to t = 0. </p>
<p>The mistake is kind of funny because error in the video is that he said, offhandedly, at some point that an object at escape velocity goes logarithmically. Well, this is the solution to the equation for how an object at escape velocity behaves, he just didn&#8217;t notice.</p>
]]></content:encoded>
	</item>
</channel>
</rss>
