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58. Stability of de Sitter space: dS as a perfect interferometer

ASTRO, HEP-TH/PH — By Dmitry Podolsky on June 13, 2008 at 1:20 pm
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Dmitry Podolsky has got his PhD from Landau Institute for Theoretical Physics. He currently works as postdoc at Case Western Reserve University. He is also one of the editors of NEQNET.

Let us now show that QFT of a massive scalar field in de Sitter space features instabilities if the number of dimensions is odd. The expression for the two-point function found in the previous post will be of no help, so we will have to switch to the language of Bogolyuov coefficients and modes.

In the global coordinates the metric of the 58. Stability of de Sitter space: dS as a perfect interferometer space is given by

58. Stability of de Sitter space: dS as a perfect interferometer (1)

where 58. Stability of de Sitter space: dS as a perfect interferometer is the metric of 58. Stability of de Sitter space: dS as a perfect interferometer-dimensional sphere. Let us consider a free massive scalar field on the de Sitter background. General solution of the Klein-Gordon equation

58. Stability of de Sitter space: dS as a perfect interferometer (2)

can be represented as a sum over spherical harmonics

58. Stability of de Sitter space: dS as a perfect interferometer (3)

where the functions 58. Stability of de Sitter space: dS as a perfect interferometer satisfy the equation

58. Stability of de Sitter space: dS as a perfect interferometer (4)

Let us introduce

58. Stability of de Sitter space: dS as a perfect interferometer (5)

In this post, we only consider the case when 58. Stability of de Sitter space: dS as a perfect interferometer is large enough for the expression above to be real (i.e., the case of heavy scalar field).

By substitution

58. Stability of de Sitter space: dS as a perfect interferometer (6)

this equation is transformed into the hypergeometric form

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer (7)

In-modes (corresponding to the absence of particles at 58. Stability of de Sitter space: dS as a perfect interferometer, i.e., at 58. Stability of de Sitter space: dS as a perfect interferometer) are given by

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer (8)

At 58. Stability of de Sitter space: dS as a perfect interferometer one has

58. Stability of de Sitter space: dS as a perfect interferometer (9)

so that in-modes are positive frequency modes at 58. Stability of de Sitter space: dS as a perfect interferometer.

Since the equation (4) is symmetric with respect to the transformation 58. Stability of de Sitter space: dS as a perfect interferometer, out-modes (corresponding to the absence of particles at 58. Stability of de Sitter space: dS as a perfect interferometer, i.e., at 58. Stability of de Sitter space: dS as a perfect interferometer) can be immediately identified as

58. Stability of de Sitter space: dS as a perfect interferometer (10)

so that

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer (11)

At 58. Stability of de Sitter space: dS as a perfect interferometer one has

58. Stability of de Sitter space: dS as a perfect interferometer (12)

so that out-modes are positive frequency modes at 58. Stability of de Sitter space: dS as a perfect interferometer. Normalization of both in- and out-modes is easily found to be

58. Stability of de Sitter space: dS as a perfect interferometer. (13)

As one may notice, both in- and out-modes are divergent at 58. Stability of de Sitter space: dS as a perfect interferometer: according to the Raabe criterion, hypergeometric series defining the functions

58. Stability of de Sitter space: dS as a perfect interferometer (14)

diverge there for any 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer. Therefore, strictly speaking, we are not allowed to calculate matrix elements between in- and out-modes directly; instead, we have to introduce some modes 58. Stability of de Sitter space: dS as a perfect interferometer regular at 58. Stability of de Sitter space: dS as a perfect interferometer to calculate the Bogolyubov coefficients 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer separately. As we see, something interesting happens near the throat 58. Stability of de Sitter space: dS as a perfect interferometer of the de Sitter hyperboloid.

(Note that Strominger, Bousso and Maloney calculate Bogolyubov coefficients between 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer directly, which is not fare way to do the caclulation from my point of view.)

To show how particles are created between 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer infinities, any choice of modes 58. Stability of de Sitter space: dS as a perfect interferometer is suitable. However, to demonstrate the physical essence of instability in de Sitter space, we choose Euclidean modes as 58. Stability of de Sitter space: dS as a perfect interferometer, since they have a remarkable property of CPT-invariance

58. Stability of de Sitter space: dS as a perfect interferometer

(compare it with the condition (10).

Normalized Euclidean modes have the form

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer (11)

where

58. Stability of de Sitter space: dS as a perfect interferometer. (12)

Using properties of the hypergeometric functions, we immediately find that

58. Stability of de Sitter space: dS as a perfect interferometer, (13)

where the Bogolyubov coefficients are

58. Stability of de Sitter space: dS as a perfect interferometer (14)

58. Stability of de Sitter space: dS as a perfect interferometer (15)

where

58. Stability of de Sitter space: dS as a perfect interferometer (16)

and the scalar product is defined as usual:

58. Stability of de Sitter space: dS as a perfect interferometer (17)

(we integrated over angles of 58. Stability of de Sitter space: dS as a perfect interferometer and used orthogonalitity of spherical harmonics).

The Bogolyubov coefficients between Euclidean and out-modes

58. Stability of de Sitter space: dS as a perfect interferometer (18)

are simply related to (14), (15). Indeed, one finds

58. Stability of de Sitter space: dS as a perfect interferometer (19)

After a trivial calculation we conclude that

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer. (20)

Therefore, there is no particle production in de Sitter space (in- and out-vacua coincide) if 58. Stability of de Sitter space: dS as a perfect interferometer. (21)

From the expressions for Bogolyubov coefficints we immediately see that

58. Stability of de Sitter space: dS as a perfect interferometer
58. Stability of de Sitter space: dS as a perfect interferometer (22)

Therefore, if 58. Stability of de Sitter space: dS as a perfect interferometer is odd, interference between 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer parts of de Sitter is desctructive, in- and out-vacua coincide (there is no overall particle production), and de Sitter space is stable. On the other hand, if d is even, interference between 58. Stability of de Sitter space: dS as a perfect interferometer and 58. Stability of de Sitter space: dS as a perfect interferometer part of de Sitter is constructive, and de Sitter space should be unstable. The distribution of particles produced in the throat is independent of the angular momentum 58. Stability of de Sitter space: dS as a perfect interferometer and is given by

58. Stability of de Sitter space: dS as a perfect interferometer, (23)

so that the total number of produced particles strongly diverges. It would be nice to see the instability of odd-dimensional de Sitter space at the level of Green’s functions though, and we will show it but not this time 58. Stability of de Sitter space: dS as a perfect interferometer

4 Comments

  1. wandering.the.cosmos says:
    June 15, 2008 at 6:45 am

    Dear Dmitry,

    Your equation (4) has contains a single tau derivative (d/d tau)y_L. I’m not sure why it is symmetric in the transformation tau -> -tau — could you explain?

    I’ve found instead, if I first substitute y_L(tau) = exp(-tau(d-1)/2) z_L(tau), then the equation takes the form

    z_L”(tau) – ( (1/4)(d(d – 2) + 1) – m^2 – L (d + L – 2) sech^2(t) ) z_L(tau) = 0,

    which can also be solved in terms of hypergeometric functions (probably similar/same answer as yours? I’ve not checked…) and is symmetric under tau -> – tau.

    I’d also like to ask you: I’ve heard before that de Sitter spacetime does not admit a S-matrix. Is this true? And is it related to this divergence at tau = 0 that you’re discussing here?

    Thank you!

    P.S. I should say I “discovered” your blog a week or two ago and I hope to read it on a regular basis and also try to learn some QFT from your older posts.

    Reply
  2. wandering.the.cosmos says:
    June 15, 2008 at 9:17 am

    I’m reading your posts backwards. Having read your post #57, I think there is simply a slight typo in your equation (4): the term with one tau derivative should be (d?1) tanh[tau] y_L’[tau], cf. eq. 3.9 of Bousso, Maloney, and Strominger [arXiv: hep-th/0112218].

    Reply
  3. Dmitry says:
    June 15, 2008 at 9:20 am

    Dear WTC

    > Your equation (4) has contains a single tau derivative (d/d > tau)y_L. I?m not sure why it is symmetric in the
    > transformation tau -> -tau ? could you explain?

    Indeed, (4) as I wrote it is not invariant w.r.t. \tau->-\tau. This is because I forgot to add \tanh \tau in the second term :-) Fixed now and thanks for finding misprint.

    > I?d also like to ask you: I?ve heard before that de Sitter > spacetime does not admit a S-matrix. Is this true? And is
    > it related to this divergence at tau = 0 that you?re
    > discussing here?

    You probably had in mind AdS, didn’t you? Quantum gravity in AdS does not have a description in terms of S-matrix, instead, one has to describe it in terms of boundary degrees of freedom (AdS/CFT).

    Actually, dS admits in-out S-matrix for odd dimensions; what I calculate is exactly S-matrix elements between in- and out-states. When number of dimensions is even, de Sitter admits in-in S-matrix (singularity at \tau=0 basically means that there is particle production and in-out S-matrix is of no good).

    Your comments and questions are very much welcome.
    Cheers.

    Reply
  4. Dmitry says:
    June 15, 2008 at 10:06 am

    Hi again WTC

    You figured out everything yourself while I was posting my answer.

    Cheers

    Reply

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